6+(-4+2)^2=3(3-x)

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Solution for 6+(-4+2)^2=3(3-x) equation: 



6+(-4+2)^2=3(3-x)

We move all terms to the left:

6+(-4+2)^2-(3(3-x))=0

We add all the numbers together, and all the variables

-(3(-1x+3))+6+(-2)^2=0

We add all the numbers together, and all the variables

-(3(-1x+3))+10=0



We calculate terms in parentheses: -(3(-1x+3)), so:

3(-1x+3)

We multiply parentheses

-3x+9

Back to the equation:

-(-3x+9)



We get rid of parentheses

3x-9+10=0

We add all the numbers together, and all the variables

3x+1=0

We move all terms containing x to the left, all other terms to the right

3x=-1

x=-1/3

x=-1/3

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